Details
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Type:
Improvement
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Status:
Closed
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Priority:
Minor
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Resolution: Fixed
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Affects Version/s: 1.0-beta-2
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Fix Version/s: 1.0-beta-3
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Component/s: parser
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Labels:None
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Number of attachments :
Description
class Tester {
static main(args) {
c = 0
println(c)
}
}
prints 0
This is because the code in curly brackets is treated as a closure not as a block.
If I write
class Tester {
static main(args) {
c = 0
if (true) { c = 9 }
println(c)
}
}
then it prints 9
The behaviour of the compiler isn't really a bug but it is surprising behaviour to a C or Java programmer.
I can see no use for the construction and immediate discarding of a closure. Would it be possible for the compiler to treat this construct as a block?